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Home»Project Management»How to estimate painting and decoration work for buildings
Project Management

How to estimate painting and decoration work for buildings

Mezie EthelbertBy Mezie EthelbertUpdated:
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There are varieties of painting materials and decorative finish available in the market. Each type of paint and decorative finish has its covering capacity in m2. This covering capacity varies between surfaces to be treated. Table 1 below shows the covering capacity of various paints per 100 m2 of wall in litres (1 litre = 0.264 gallons). The choice of the type of type of paint for buildings or other works depends on many factors some of which can be found HERE.

Table 1; Paint covering capacity

Covering capacity per 100 m2 (1 coat only)Volume (litres)
Alkaline resisting primer to lime plaster9
Alkaline resisting primer to brick/block work13
Wood primer9
Metal primer6.25
Undercoat7
Gloss paint8
Eggshell paint7
Emulsion paint7
Bituminuous paint10
Sandtex-Matt21
Staining7
Synthetic Varnish5.5
Aluminum6
Knotting           (Extreme case)                          Minimum (Average)0.57 0.30
Putty for stopping1.5 – 2.5 kg
Sand-paper for preparing8 sheets
Snowcam40 kg
Sandtex-textured95 kg

Estimation of paint requirement for a small building

To get the paint requirement for a building requires first to find the area of the spaces to be painted. Figure 1 below shows a small building in which it is required to find the paint requirement for the internal spaces of the building.

Figure 1; Small building

The internal spaces of the building comprise:

  1. The parlour
  2. The bedroom
  3. Toilet, and
  4. Kitchen

If the headroom of the building 3 m across all spaces;

The parlour

The area of parlour = 15.3 m (perimeter) x 3 m (height or headroom) = 45.9 m2 – (window spaces + door spaces)

Window spaces = 1 m (length) x 1.2 m (height) x 2 (number) = 2.4 m2

Door spaces = 0.9 m x 2.1 m x 2 = 3.78 m2

Net area to be painted = 45.9 – 2.4 – 3.78 = 39.72 m2

The bedroom

The area of bedroom = 12.9 x 3 = 38.7 m2

Window spaces = 1 x 1.2 = 1.2 m2

Door spaces = (0.9 x 2.1 x 2) + (0.75 x 2.1 x 2) = 3.78 + 3.15 = 6.93 m2

Net area to be painted = 38.7 – 1.2 – 6.93 = 30.57 m2

Toilet

The area of toilet = 6 x 3 = 18 m2

Window spaces = 0.6 x 0.6 = 0.36 m2

Door spaces = 0.75 x 2.1 = 1.575 m2

Net area to be painted = 18 – 0.36 – 1.575 = 16.065 m2

Kitchen

The area of kitchen = 6.6 x 3 = 19.8 m2

Window spaces = 0.6 x 0.9 = 0.54 m2

Door spaces = 0.75 x 2.1 = 1.575 m2

Net area to be painted = 19.8 – 0.54 – 1.575 = 17.685 m2

Total net area to be painted = area of parlour + area of bedroom + area of toilet + area of kitchen

= 39.72 + 30.57 + 16.065 + 17.685 = 104.04 m2

Assuming an emulsion paint of 7 litres/100 m2 would be used for the surfaces and be applied in three coats, the coverage capacity would reduce with subsequent coats as follows:

1st coat = 7 litres/100 m2

2nd coat = 6.65 litres/100 m2

3rd coat = 6.30 litres/100 m2

It implies that the three coats would require a total of 7 + 6.65 + 6.3 = 19.95 litres/100 m2

104.04 m2 of wall would require (104.4 x 19.95) / 100 = 20.8 litres ≈ 21 litres

It implies that 21 litres (0.021 m3) or 5.5 gallons of EMULSION PAINT would be required to paint the internal spaces of the building.

Thanks for reading!

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Mezie Ethelbert

An inquisitive engineer with considerable skills in analysis, design and research in the field of civil engineering.

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